Find analytical expressions for the magnitude and phase response for each G(s) below. [Section: 10.1] a. G(s) = \(\frac{1}{s(s+2)(s+4)}\) b. G(s) = \(\frac{(s+5)}{(s+2)(s+4)}\) c. G(s) = \(\frac{(s+3)(s+5)}{s(s+2)(s+4)}\)
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Textbook Solutions for Control Systems Engineering
Question
A room's temperature can be controlled by varying the radiator power. In a specific room, the transfer function from indoor radiator power, \(\dot{Q}\), to room temperature, T in \({ }^{\circ} \mathrm{C}\) is (Thomas, 2005)
P(s) = \(\frac{T(s)}{\dot{Q}(s)}\)
= \(\frac{\left(1 \times 10^{-6}\right) s^2+\left(1.314 \times 10^{-9}\right) s+\left(2.66 \times 10^{-13}\right)}{s^3+0.00163 s^2+\left(5.272 \times 10^{-7}\right) s+\left(3.538 \times 10^{-11}\right)}\)
The system is controlled in the closed-loop configuration shown in Figure 10.20 with G(s) = KP(s), H = 1.
a. Draw the corresponding Nyquist diagram for K = 1.
b. Obtain the gain and phase margins.
c. Find the range of K for the closed-loop stability. Compare your result with that of Problem 58, Chapter 6.
Solution
The first step in solving 10 problem number 35 trying to solve the problem we have to refer to the textbook question: A room's temperature can be controlled by varying the radiator power. In a specific room, the transfer function from indoor radiator power, \(\dot{Q}\), to room temperature, T in \({ }^{\circ} \mathrm{C}\) is (Thomas, 2005)P(s) = \(\frac{T(s)}{\dot{Q}(s)}\) = \(\frac{\left(1 \times 10^{-6}\right) s^2+\left(1.314 \times 10^{-9}\right) s+\left(2.66 \times 10^{-13}\right)}{s^3+0.00163 s^2+\left(5.272 \times 10^{-7}\right) s+\left(3.538 \times 10^{-11}\right)}\)The system is controlled in the closed-loop configuration shown in Figure 10.20 with G(s) = KP(s), H = 1.a. Draw the corresponding Nyquist diagram for K = 1.b. Obtain the gain and phase margins.c. Find the range of K for the closed-loop stability. Compare your result with that of Problem 58, Chapter 6.
From the textbook chapter FREQUENCY RESPONSE TECHNIQUES you will find a few key concepts needed to solve this.
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