Solution Found!
Kinetic-Molecular Theory of Gases: Effusion and
Chapter , Problem 86E(choose chapter or problem)
Problem 86e
Kinetic-Molecular Theory of Gases: Effusion and Diffusion (Sections)
At constant pressure, the mean free path (A) of a gas molecule is directly proportional to temperature. At constant temperature, A is inversely proportional to pressure. If you compare two different gas molecules at the same temperature and pressure, A is inversely proportional to the square of the diameter of the gas molecules. Put these facts together to create a formula for the mean free path of a gas molecule with a proportionality constant (call it Pmfp. Ike the ideal-gas constant) and define units for Pmfp.
Questions & Answers
QUESTION:
Problem 86e
Kinetic-Molecular Theory of Gases: Effusion and Diffusion (Sections)
At constant pressure, the mean free path (A) of a gas molecule is directly proportional to temperature. At constant temperature, A is inversely proportional to pressure. If you compare two different gas molecules at the same temperature and pressure, A is inversely proportional to the square of the diameter of the gas molecules. Put these facts together to create a formula for the mean free path of a gas molecule with a proportionality constant (call it Pmfp. Ike the ideal-gas constant) and define units for Pmfp.
ANSWER:Step 1 of 3
From the given, the pressure is constant, the mean free path of a gas molecule is proportional to the temperature.
This can be represented as follows:
..........................(1)
When the temperature is constant, the mean free path $(\lambda)$ for the same gas molecule is inversely proportional to pressure.
This gives the following relation:
..............................(2)
From relations (1) and (2) the possible relation between , and is given below:
..................(3)