Solved: Determining Relative Strengths of Oxidizing
Chapter , Problem 1PE(choose chapter or problem)
Problem 1PE
Determining Relative Strengths of Oxidizing Agents
Using Table rank the following ions in the order of increasing strength as oxidizing agents: NO3–(aq), Ag+(aq), Cr2O72–.
Table Standard Reduction Potentials in Water at 25°c
Eºred(V) |
Reduction Half–Reaction |
+2.87 |
F2(g) + 2 e–→.2 F–(aq) |
+1.51 |
MnO4–(aq) + 8 H+(aq) + 5 e–→.Mn2+(aq) + 4 H2O(l) |
+1.36 |
Cl2(g) + 2 e–→.2 Cl–(aq) |
+1.33 |
Cr2O72–(aq) + 14 H+(aq) + 6 e–→.2 Cr3+(aq) + 7 H2O(l) |
+1.23 |
O2(g) + 4 H+(aq) + 4 e–→.2 H2O(l) |
+1.06 |
Br2(l) + 2 e–→.2 Br–(aq) |
+0.96 |
NO3–(aq) + 4 H+(aq) + 3 e–→.NO(g) + 2 H2O(l) |
+0.80 |
Ag+(aq) + e–→.Ag(s) |
+0.77 |
Fe3+(aq) + e–→.Fe2+(aq) |
+0.68 |
O2(g) + 2 H+(aq) + 2 e–→.H2O2(aq) |
+0.59 |
MnO4–(aq) + 2 H2O(l) + 3 e–→.MnO2(s) + 4 OH–(aq) |
+0.54 |
l2(s) + 2 e–→.2 l–(aq) |
+0.40 |
O2(g) + 2 H2O(l) + 4 e–→.4 OH–(aq) |
+0.34 |
Cu2+(aq) + 2 e–→.Cu |
0 [defined] |
2 H+(aq) + 2 e–→.H2(g) |
–0.28 |
Ni2+(aq) + 2 e–→.Ni(s) |
–0.44 |
Fe2+ (aq) + 2 e–→.Fe(s) |
–0.76 |
Zn2+(aq) + 2 e–→.Zn(s) |
–0.83 |
2 H2O(l) + 2 e–→.H2(g) + 2 OH–(aq) |
–1.66 |
Al3+(aq) + 3 e–→.Al(s) |
–2.71 |
Na+(aq) + e–→.Na(s) |
–3.05 |
Li+(aq) + e–→.Li(s) |
Based on the data in Table 20.1 which of the following species would you expect to be the strongest oxidizing agent?
(a) Cl–(aq), (b) Cl2(g), (c) O2(g), (d) H+(aq), (e) Na+(aq).
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