Solved: Trajectory high point A stone is launched
Chapter 4, Problem 51(choose chapter or problem)
Trajectory high point A stone is launched vertically upward from a cliff 192 feet above the ground at a speed of 64 ft>s. Its height above the ground t seconds after the launch is given by s = -16t2 + 64t + 192, for 0 t 6. When does the stone reach its maximum height?
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