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Projectile Motion: Calculating Horizontal and Vertical Distances
Chapter 3, Problem 25(choose chapter or problem)
A projectile is launched at ground level with an initial speed of 50.0 m/s at an angle of 30.0º above the horizontal. It strikes a target above the ground 3.00 seconds later. What are the x and y distances from where the projectile was launched to where it lands?
Questions & Answers
QUESTION:
A projectile is launched at ground level with an initial speed of 50.0 m/s at an angle of 30.0º above the horizontal. It strikes a target above the ground 3.00 seconds later. What are the x and y distances from where the projectile was launched to where it lands?
ANSWER:Step 1 of 5:
In this question, we need to find the x and y distances from the initial to final position of projectile
Data given
Velocity, \(v=50.0 \mathrm{m} / \mathrm{s}\)
Angle of projection, \(\theta=30.0^{\circ}\)
Time taken, \(t=3.00 \mathrm{s}\)
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Projectile Motion: Calculating Horizontal and Vertical Distances
Want To Learn More? To watch the entire video and ALL of the videos in the series:
Dive into the world of projectile motion as we calculate the horizontal and vertical distances a launched projectile covers. Explore the impact of angle and speed on the trajectory, all explained in this engaging video.