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Integrated Concepts A basketball player jumps straight up

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 46PE Chapter 4

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 46PE

Problem 46PE

Integrated Concepts A basketball player jumps straight up for a ball. To do this, he lowers his body 0.300 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.900 m above the floor. (a) Calculate his velocity when he leaves the floor. (b) Calculate his acceleration while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.300 m. (c) Calculate the force he exerts on the floor to do this, given that his mass is 110 kg.

Step-by-Step Solution:

Solution 46PE

The basketball player wants to reach a given height. From this, we have to calculate the velocity when he jumps from the floor. From this data, we can further calculate the acceleration. We are also required to calculate the force exerted by him on the ground.

Part a

Step 1 of 3

At the maximum height, his final velocity  would be zero.

Let the initial velocity be .

Height to reach m

From the equation,

, (negative symbol as he moves up)

m/s2m

m/s

m/s

Therefore, his velocity while leaving the floor will be 4.20 m/s.



Part b

Step 2 of 3

Chapter 4, Problem 46PE is Solved
Step 3 of 3

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

The answer to “Integrated Concepts A basketball player jumps straight up for a ball. To do this, he lowers his body 0.300 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.900 m above the floor. (a) Calculate his velocity when he leaves the floor. (b) Calculate his acceleration while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.300 m. (c) Calculate the force he exerts on the floor to do this, given that his mass is 110 kg.” is broken down into a number of easy to follow steps, and 104 words. The full step-by-step solution to problem: 46PE from chapter: 4 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. This full solution covers the following key subjects: floor, velocity, calculate, Legs, player. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. Since the solution to 46PE from 4 chapter was answered, more than 2874 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: College Physics , edition: 1. College Physics was written by and is associated to the ISBN: 9781938168000.

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Integrated Concepts A basketball player jumps straight up