In this problem we explore a little further the analogy

Chapter 11, Problem 27

(choose chapter or problem)

In this problem we explore a little further the analogy between SturmLiouville boundaryvalue problems and Hermitian matrices. Let A be an n n Hermitian matrix witheigenvalues 1, ... , n and corresponding orthogonal eigenvectors (1), ... , (n).Consider the nonhomogeneous system of equationsAx x = b, (i)where is a given real number and b is a given vector. We will point out a way of solvingEq. (i) that is analogous to the method presented in the text for solving Eqs. (1) and (2).(a) Show that b = ni=1bi(i), where bi = (b, (i)).(b) Assume that x = ni=1ai(i) and show that for Eq. (i) to be satisfied, it is necessary thatai = bi/(i ). Thusx = ni=1(b, (i))i (i), (ii)provided that is not one of the eigenvalues of A, = i for i = 1, ... , n. Compare thisresult with Eq. (13).Greens7 Functions. Consider the nonhomogeneous system of algebraic equationsAx x = b, (i)where A is an n n Hermitian matrix, is a given real number, and b is a given vector. Insteadof using an eigenvector expansion as in 27, we can solve Eq. (i) by computing theinverse matrix (A I)1, which exists if is not an eigenvalue of A. Thenx = (A I)1b. (ii)

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back