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# Thomson’s Model of the Atom, Continued. Using Thomson’s ISBN: 9780321675460 31

## Solution for problem 55P Chapter 22

University Physics | 13th Edition

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Problem 55P

Step-by-Step Solution:

Solution 55P Step 1 of 5: The electron 1 exerts force on 2 and also electron 2 exerts force on electron 1. According to Coulomb’s law, the force between the electrons. Consider the forces on the electron 2. There is a repulsive force F due to the 1ther electron because both are same(negative) charge. where 2d is the distance between the electrons .R is the radius of the sphere. F = 1 e2 1 40(2d)2 2 = 1 e 2............................(1) 404d Step 2 of 5: The electric field inside the uniform distribution of positive charge is Qr E = 1 3 where Q =+ 2e 40R Step 3 of 5: At the position electron 2, r = d and force F exerted by positive charge distribution is cd e(2e)d F cd = eE = 4 R3 0 2e d = 3 40R this is attractive force .

Step 4 of 5

Step 5 of 5

##### ISBN: 9780321675460

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