Solution Found!
(a) An electron is to be accelerated from 3.00 X 106 m/s
Chapter 23, Problem 23E(choose chapter or problem)
(a) An electron is to be accelerated from 3.00 X 106 m/s to 8.00 X 106 m/s. Through what potential difference must the electron pass to accomplish this? (b) Through what potential difference must the electron pass if it is to be slowed from 8.00 X 106 m/s to a halt?
Questions & Answers
QUESTION:
(a) An electron is to be accelerated from 3.00 X 106 m/s to 8.00 X 106 m/s. Through what potential difference must the electron pass to accomplish this? (b) Through what potential difference must the electron pass if it is to be slowed from 8.00 X 106 m/s to a halt?
ANSWER:Introduction We have to calculate the required potential difference to accelerate an electron from 3.00 × 10 6 m/s to 8.00 × 10 m/s. Then we have to calculate the required potential energy to stop an electron from 8.0 × 106m/s to halt. Step 1 (a) In this case the increase in the kinetic energy will be supplied by the potential difference. So we will equate the change in kinetic energy and change in electrical potential energy to calculate the required change in potential difference. The change in kinetic energy is given by So now the change in the potential energy is given by So equating we have For electron we have and the velocities are Hence the required potential energy is Negative sign indicates that the direction of the potential difference will be opposite to the direction of the velocity. 6 Hence the potential difference required to accelerate the electron from 3.00 × 10 m/s velocity to 8.00 × 10 m/s velocity is 157 V.