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For the capacitor network shown in Fig, the 150 nF 1.20 nF
Chapter 24, Problem 30E(choose chapter or problem)
For the capacitor network shown in Fig, the 150 nF 1.20 nF potential difference across ab is 36 V. Find (a) the total charge stored in this network; (b) the charge on each capacitor; (c) the total energy stored in the network; (d) the energy stored in each capacitor; (e) the potential differences across each capacitor. Figure:
Questions & Answers
QUESTION:
For the capacitor network shown in Fig, the 150 nF 1.20 nF potential difference across ab is 36 V. Find (a) the total charge stored in this network; (b) the charge on each capacitor; (c) the total energy stored in the network; (d) the energy stored in each capacitor; (e) the potential differences across each capacitor. Figure:
ANSWER:Introduction We have to calculate the total charge of the combination of capacitor and then charge on each capacitor. Then we have to calculate the total charge of the combination and the charge stored in each capacitor. Then we have to calculate the voltage across each capacitor. Step 1 (a) Here the capacitor are connected in series, and the equivalent capacitance for series combination is given by Now we have C 1 150 nF and C = 220 nF Hence we have Now the voltage of the network is V = 36 V. Hence the charge stored in the network is given by Hence the total charge stored in the network is 2.40 µC.