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Integrated ConceptsFigure 18.57 shows an electron passing

Chapter 18, Problem 61

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QUESTION:

Integrated Concepts

Figure \(18.57\) shows an electron passing between two charged metal plates that create an \(100 \mathrm{~N} / \mathrm{C}\) vertical electric field perpendicular to the electron’s original horizontal velocity. (These can be used to change the electron’s direction, such as in an oscilloscope.) The initial speed of the

electron is \(3.00 \times 10^{6} \mathrm{~m} / \mathrm{s}\) , and the horizontal distance it travels in the uniform field is \(4.00 cm\).

(a) What is its vertical deflection?

(b) What is the vertical component of its final velocity?

(c) At what angle does it exit? Neglect any edge effects.

Figure \(18.57\)

Equation Transcription:

4.00 cm

Text Transcription:

18.57

100 N/C

3.00 times 10^6 m/s

4.00 cm

Questions & Answers

QUESTION:

Integrated Concepts

Figure \(18.57\) shows an electron passing between two charged metal plates that create an \(100 \mathrm{~N} / \mathrm{C}\) vertical electric field perpendicular to the electron’s original horizontal velocity. (These can be used to change the electron’s direction, such as in an oscilloscope.) The initial speed of the

electron is \(3.00 \times 10^{6} \mathrm{~m} / \mathrm{s}\) , and the horizontal distance it travels in the uniform field is \(4.00 cm\).

(a) What is its vertical deflection?

(b) What is the vertical component of its final velocity?

(c) At what angle does it exit? Neglect any edge effects.

Figure \(18.57\)

Equation Transcription:

4.00 cm

Text Transcription:

18.57

100 N/C

3.00 times 10^6 m/s

4.00 cm

ANSWER:

Solution

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