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# Solution: In each of 1 through 10, write the Fourier integral representation (14.1) of

ISBN: 9781111427412 173

## Solution for problem 14.5 Chapter 14

Advanced Engineering Mathematics | 7th Edition

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Advanced Engineering Mathematics | 7th Edition

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Problem 14.5

In each of 1 through 10, write the Fourier integral representation (14.1) of the function and determine what this integral converges to.f (x) = x 2 for 100 x 100 0 for |x| > 100

Step-by-Step Solution:
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Calculus notes for week of 9/19/16 3.6 Derivatives as Rates of Change Velocity is measured as: V ave(t+∆t) or s(b) – s(a) ∆t b – a (Change in position over change in time.) S’’(t) = V’(t) = A(t) (From left to right: S=Position, V= Velocity, and A=Acceleration) Average and Marginal Cost Suppose C(x) gives the total cost to produce x units of a good cost. Sometimes, C(x) = FC + VC * x FC = Fixed cost which does not change with units produced. VC = Variable cost which is the cost to produce each unit. C(x) = Average cost. C’(x) = Marginal cost, which is approximately the extra cost to produce one more unit beyond x units. C’(x) = lim C(x+∆x) – C(x) ∆x>0 ∆x 3.7 Chain Rule How do we differentiate a composi

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##### ISBN: 9781111427412

The answer to “In each of 1 through 10, write the Fourier integral representation (14.1) of the function and determine what this integral converges to.f (x) = x 2 for 100 x 100 0 for |x| > 100” is broken down into a number of easy to follow steps, and 35 words. Since the solution to 14.5 from 14 chapter was answered, more than 257 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Advanced Engineering Mathematics, edition: 7. Advanced Engineering Mathematics was written by and is associated to the ISBN: 9781111427412. This full solution covers the following key subjects: . This expansive textbook survival guide covers 23 chapters, and 1643 solutions. The full step-by-step solution to problem: 14.5 from chapter: 14 was answered by , our top Math solution expert on 12/23/17, 04:48PM.

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