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# Show that, if r > 0, then for any positive x, (x) =r x 0

ISBN: 9781111427412 173

## Solution for problem 15.69 Chapter 15

Advanced Engineering Mathematics | 7th Edition

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Advanced Engineering Mathematics | 7th Edition

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Problem 15.69

Show that, if r > 0, then for any positive x, (x) =r x 0 ert t x1 dt. Hint: Let t =r y in the definition of (x).

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Overview week of 9/12/16 3.3 Rules of Differentiation Power of X: d n (n­1) Power Rule: / Xdx= nX Quotient Rule: / f(x)/g(x) = [(f(x) * g(x)) – (f(x) * g(x))] / [g(x)] 2 dx Product Rule: / [dxx) * g(x)] = [f(x) * g’(x)] + [g(x) * f’(x)] Chain Rule: / [dxg(x))] = [f(g(x))]’ * g’(x) Constant Multiple: Power rule d /dx(cf(x)) = c * f ’(x) 3.4...

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##### ISBN: 9781111427412

This full solution covers the following key subjects: . This expansive textbook survival guide covers 23 chapters, and 1643 solutions. Since the solution to 15.69 from 15 chapter was answered, more than 219 students have viewed the full step-by-step answer. Advanced Engineering Mathematics was written by and is associated to the ISBN: 9781111427412. This textbook survival guide was created for the textbook: Advanced Engineering Mathematics, edition: 7. The answer to “Show that, if r > 0, then for any positive x, (x) =r x 0 ert t x1 dt. Hint: Let t =r y in the definition of (x).” is broken down into a number of easy to follow steps, and 29 words. The full step-by-step solution to problem: 15.69 from chapter: 15 was answered by , our top Math solution expert on 12/23/17, 04:48PM.

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