Solved: In 31–34, solve the given initial value problem.

Chapter 9, Problem 32E

(choose chapter or problem)

$x^{\prime}(t)=\left[\begin{array}{ll} 6 & -3 \\ 2 & 1 \end{array}\right] x(t)$

$x(0)=\left[\begin{array}{c} -10 \\ -6 \end{array}\right]$

Equation Transcription:

$x'(t)=$ [ ${\ }_{\ \ 2\ \ \ \ \ \ 1}^{\ \ 6\ \ \ \ -3\ }$ ] $x(t)$

$x(0)=$ [ ${\ }_{\ \ \ -6}^{\ \ -10\ \ }$ ]

Text Transcription:

x'(t)=[ 2 1 6 -3 ]x(t)

x(0)=[ -6 -10 ]

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