Solution Found!
is exact.
Chapter 2, Problem 27E(choose chapter or problem)
QUESTION:
In Problems 27 and 28 find the value of k so that the given differential equation is exact.
\(\left(y^{3}+k x y^{4}-2 x\right) \ d x+\left(3 x y^{2}+20 x^{2} y^{3}\right) \ d y=0\)
Text Transcription:
(y^3 + kxy^4 - 2x) dx + (3xy^2 + 20x^2 y^3) dy = 0
Questions & Answers
QUESTION:
In Problems 27 and 28 find the value of k so that the given differential equation is exact.
\(\left(y^{3}+k x y^{4}-2 x\right) \ d x+\left(3 x y^{2}+20 x^{2} y^{3}\right) \ d y=0\)
Text Transcription:
(y^3 + kxy^4 - 2x) dx + (3xy^2 + 20x^2 y^3) dy = 0
ANSWER:Step 1 of 3
In this problem we need to find the value of k so that the given differential equation is exact.