Suppose the solution of the boundary-value problem and are
Chapter 4, Problem 45E(choose chapter or problem)
Suppose the solution of the boundary-value problem
\(y^{\prime \prime}+P y^{\prime}+Q y=f(x), y(a)=0, y(b)=0\), a < b is given by, \(y_{p}(x)=\int_{a}^{b} G(x, t) f(t) d t\) where \(y_{1}(x)\) and y_{2}(x) are solutions of the associated homogeneous differential equation chosen in the construction of G(x, t) so that \(y_{1}(a)=0 \text { and } y_{2}(b)=0\). Prove that the solution of the boundary-value problem with nonhomogeneous DE and boundary conditions,
\(y^{\prime \prime}+P y^{\prime}+Q y=f(x), y(a)=A, y(b)=B\)
is given by
\(y(x)=y_{p}(x)+\frac{B}{y_{1}(b)} y_{1}(x)+\frac{A}{y_{2}(a)} y_{2}(x)\)
[Hint: In your proof, you will have to show that \(y_{1}(b) \neq 0 \text { and } y_{2}(a) \neq 0\). Reread the assumptions following (24).]
Text Transcription:
y^prime prime+P y^prime+Q y=f(x), y(a)=0, y(b)=0
y_{p}(x)=int_{a}^{b} G(x, t) f(t) d t
y_1x
y_2x
y_1a=0
y_2b=0
y^prime prime+P y^prime+Q y=f(x), y(a)=A, y(b)=B
y(x)=y_px+fracBy_1b y_1x+fracAy_2a y_2x
y_1b neq 0
y_2aneq 0
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer