Solution: In 29–34 solve the given differential equation
Chapter , Problem 38RP(choose chapter or problem)
In Problems 35–40 solve the given differential equation subject to the indicated conditions.
\(y^{\prime \prime}+y=\sec ^{3} x, \quad y(0)=1, y^{\prime}(0)=\frac{1}{2}\)
Text Transcription:
y^prime\prime+y=sec^3x,y(0)=1,y^prime(0)=frac12
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