Solved: Electricity: Kirchhoffs Rules An application of

Chapter 12, Problem 84

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Electricity: Kirchhoffs Rules An application of Kirchhoffs Rules to the circuit shown results in the following system of equations: Find the currents and I3 I . 1 , I2 , c I1 = I3 + I2 24 - 6I1 - 3I3 = 0 12 + 24 - 6I1 - 6I2 = 0 Source: Ibid., Prob. 38, p. 791.

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