In Chapter 25, we found the on-axis potential of a ring of
Chapter 26, Problem 26.10(choose chapter or problem)
In Chapter 25, we found the on-axis potential of a ring of radius R and charge Q to be Vring = 1 4pP0 Q 2z 2 + R2 Find the on-axis electric field of a ring of charge. SOLVE Symmetry requires the electric field along the axis to point straight outward from the ring with only a z-component Ez. The electric field at position z is Ez = - dV dz = - d dz 1 1 4pP0 Q 2z 2 + R2 2 = 1 4pP0 zQ 1z 2 + R2 23/2
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