FIGURE CP35.50 shows a simple zoom lens in which the
Chapter 35, Problem 35.79(choose chapter or problem)
FIGURE CP35.50 shows a simple zoom lens in which the magnitudes of both focal lengths are f. If the spacing d 6 f, the image of the converging lens falls on the right side of the diverging lens. Our procedure of letting the image of the first lens act as the object of the second lens will continue to work in this case if we use a negative object distance for the second lens. This is called a virtual object. Consider an object very far to the left 1s 2 of the converging lens. Define the effective focal length as the distance from the midpoint between the lenses to the final image. a. Show that the effective focal length is feff = f 2 - fd + 1 2 d2 d b. What is the zoom for a lens that can be adjusted from d = 1 2 f to d = 1 4 f ?
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