?43PE (a) Calculate the energy released in the

QUESTION:

(a) Calculate the energy released in the neutron-induced fission (similar to the spontaneous fission in Example 32.3)

\(n+^{238}\mathrm{U}\ \rightarrow\ ^{96}\mathrm{Sr}+^{140}\mathrm{Xe}+3n\),

given \(m\left(^{96}\mathrm{Sr}\right)=95.921750\mathrm{\ u}\) and \(m\left({ }^{140} \mathrm{Xe}\right)=139.92164\). (b) This result is about \(6 \ MeV\) greater than the result for spontaneous fission. Why? (c) Confirm that the total number of nucleons and total charge are conserved in this reaction.

Equation Transcription:

Text Transcription:

n + ^238 U rightarrow ^96 Sr + ^140 Xe + 3n

m (^96 Sr) = 95.921750 u

m (^140 Xe) = 139.92164

6  MeV