Let y !x 2 "x !2 x 3 "6 then y%! !x 3 "6"d dx !x 2 "x
Chapter 3, Problem 3.88(choose chapter or problem)
Let y !x 2 "x !2 x 3 "6 then y%! !x 3 "6"d dx !x 2 "x !2"!!x 2 "x !2"d dx !x 3 "6" !x 3 "6" 2 !!x 3 "6"!2x "1"!!x 2 "x !2"!3x 2 " !x 3 "6" 2 !!2x 4 "x 3 "12x "6"!!3x 4 "3x 3 !6x 2 " !x 3 "6" 2 !!x 4 !2x 3 "6x 2 "12x "6 !x 3 "6" 2
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