Mark each statement as True or False. Justify each

Chapter , Problem 1E

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QUESTION:

Mark each statement as True or False. Justify each answer.a. If A is invertible and 1 is an eigenvalue for A, then 1 is also an eigenvalue of A–1.b. If A is row equivalent to the identity matrix I , then A is diagonalizable.c. If A contains a row or column of zeros, then 0 is an eigenvalue of A.d. Each eigenvalue of A is also an eigenvalue of A2e. Each eigenvector of A is also an eigenvector of A2.f. Each eigenvector of an invertible matrix A is also an eigenvector of A1g. Eigenvalues must be nonzero scalars.h. Eigenvectors must be nonzero vectors.i. Two eigenvectors corresponding to the same eigenvalue are always linearly dependent.j. Similar matrices always have exactly the same eigenvalues.k. Similar matrices always have exactly the same eigenvectors.l. The sum of two eigenvectors of a matrix A is also an eigenvector of A.m. The eigenvalues of an upper triangular matrix A are exactly the nonzero entries on the diagonal of A.n. The matrices A and AT have the same eigenvalues, counting multiplicities.o. If a 5 × 5 matrix A has fewer than 5 distinct eigenvalues, then A is not diagonalizable.p. There exists a 2 × 2 matrix that has no eigenvectors in .q. If A is diagonalizable, then the columns of A are linearly independent.r. A nonzero vector cannot correspond to two different eigenvalues of A.s. A (square) matrix A is invertible if and only if there is a coordinate system in which the transformation is represented by a diagonal matrix.t. If each vector ej in the standard basis for is an eigenvector of A, then A is a diagonal matrix.u. If A is similar to a diagonalizable matrix B, then A is also diagonalizable.v. If A and B are invertible n × n matrices, then AB is similar to BA.w. An n × n matrix with n linearly independent eigenvectors is invertible.x. If A is an n × n diagonalizable matrix, then each vector in can be written as a linear combination of eigenvectors of A.

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QUESTION:

Mark each statement as True or False. Justify each answer.a. If A is invertible and 1 is an eigenvalue for A, then 1 is also an eigenvalue of A–1.b. If A is row equivalent to the identity matrix I , then A is diagonalizable.c. If A contains a row or column of zeros, then 0 is an eigenvalue of A.d. Each eigenvalue of A is also an eigenvalue of A2e. Each eigenvector of A is also an eigenvector of A2.f. Each eigenvector of an invertible matrix A is also an eigenvector of A1g. Eigenvalues must be nonzero scalars.h. Eigenvectors must be nonzero vectors.i. Two eigenvectors corresponding to the same eigenvalue are always linearly dependent.j. Similar matrices always have exactly the same eigenvalues.k. Similar matrices always have exactly the same eigenvectors.l. The sum of two eigenvectors of a matrix A is also an eigenvector of A.m. The eigenvalues of an upper triangular matrix A are exactly the nonzero entries on the diagonal of A.n. The matrices A and AT have the same eigenvalues, counting multiplicities.o. If a 5 × 5 matrix A has fewer than 5 distinct eigenvalues, then A is not diagonalizable.p. There exists a 2 × 2 matrix that has no eigenvectors in .q. If A is diagonalizable, then the columns of A are linearly independent.r. A nonzero vector cannot correspond to two different eigenvalues of A.s. A (square) matrix A is invertible if and only if there is a coordinate system in which the transformation is represented by a diagonal matrix.t. If each vector ej in the standard basis for is an eigenvector of A, then A is a diagonal matrix.u. If A is similar to a diagonalizable matrix B, then A is also diagonalizable.v. If A and B are invertible n × n matrices, then AB is similar to BA.w. An n × n matrix with n linearly independent eigenvectors is invertible.x. If A is an n × n diagonalizable matrix, then each vector in can be written as a linear combination of eigenvectors of A.

ANSWER:

Solution 1E(a)Since x is nonzero, 1 is an eigenvalue of The given statement is true.(b)The matrix A is not diagonalizable.The given statement is false.(c)If A contains row of column of zero, then A is not row equivalent to the identity matrix and thus is not invertible.By the invertible matrix theorem, 0 is an eigenvalue of A.The given statement is true.(d)So is an eigenvalue for the matrix The given statement is true only for =1 and not for each eigenvalue.The given statement is false.(e)This shows that x is also an eigenvector for.The given statement is true.(f)This result shows that x is also an eigenvector of .The given statement is true.(g)Zero is an eigenvalue of any singular square matrix.So, an eigenvalue need not be a nonzero scalar.Hence, the given statement is false.(h)An eigenvector of an matrix is a nonzero vector x such thatx= xFor some scalar which is called the eigenvalue of .The given statement is true.(i)These are linearly independent.The given statement is false.(j)Similar matrices always have exactly the same eigenvalues.This is always true similar matrices.Hence, the give

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