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The initial speed of a 2.4-kg box traveling up a plane
Chapter , Problem 69(choose chapter or problem)
The initial speed of a 2.4-kg box traveling up a plane inclined \(37^{\circ}\) to the horizontal is 3.8 m/s. The coefficient of kinetic friction between the box and the plane is 0.30.
(a) How far along the incline does the box travel before coming to a stop?
(b) What is its speed when it has traveled half the distance found in Part (a)?
Questions & Answers
QUESTION:
The initial speed of a 2.4-kg box traveling up a plane inclined \(37^{\circ}\) to the horizontal is 3.8 m/s. The coefficient of kinetic friction between the box and the plane is 0.30.
(a) How far along the incline does the box travel before coming to a stop?
(b) What is its speed when it has traveled half the distance found in Part (a)?
ANSWER:Step 1 of 6
(a) In this part of the problem, we are asked to calculate the distance traveled by the box. The known values are given as follows
\(m=2.4 \mathrm{~kg}\)
\(\theta=37^{\circ}\)
\(v_{0}=3.8 \frac{\mathrm{m}}{\mathrm{s}}\)
\(v=0\)
\(\mu_{\mathrm{k}}=0.30\)