Solution Found!
Using p ? v ? T DataAs shown in Fig. P3.31, a cylinder
Chapter 3, Problem 31P(choose chapter or problem)
As shown in Fig. P3.31, a cylinder fitted with a piston is filled with \(600 \mathrm{lb}\) of saturated liquid ammonia at \(45^{\circ} \mathrm{F}\). The piston weighs 1 ton and has a diameter of \(2.5 \mathrm{ft}\). What is the volume occupied by the ammonia, in \(\mathrm{ft}^3\) ? Ignoring friction, is it necessary to provide mechanical attachments, such as stops, to hold the piston in place? Explain.
Questions & Answers
QUESTION:
As shown in Fig. P3.31, a cylinder fitted with a piston is filled with \(600 \mathrm{lb}\) of saturated liquid ammonia at \(45^{\circ} \mathrm{F}\). The piston weighs 1 ton and has a diameter of \(2.5 \mathrm{ft}\). What is the volume occupied by the ammonia, in \(\mathrm{ft}^3\) ? Ignoring friction, is it necessary to provide mechanical attachments, such as stops, to hold the piston in place? Explain.
ANSWER:
Step 1 of 2
We have to find the volume occupied by 600 lb of saturated liquid ammonia at 45°F
in a cylinder fitted with a piston which weighs 1 ton and has a diameter of 2.5 ft.
The ammonia is in saturated liquid state at a temperature of . By referring to the table A-13 available in the book Fundamentals of Engineering Thermodynamics, 7th Edition ,the specific volume
at
is
= 1.5936
m3/kg
Now,
where, volume occupied by ammonia in ft3
mass of ammonia = 600 lb
Conversion of 1.5936m3/kg to ft3/lb
1 m3/kg= 16.0185 ft3/lb
So, 1.5936m3/kg =
ft3/lb
= 25,627.50 ft3/lb
Hence, the volume occupied by ammonia is
= ( 25,627.50 )(ft3/lb) 600 (lb)
= 15,376,500 ft3
Therefore, the volume occupied by the ammonia, in ft3 is 15,376,500 ft3.