Solution Found!
Answer: Using u?h Data Using the tables for water,
Chapter 3, Problem 45P(choose chapter or problem)
Using the tables for water, determine the specified property data at the indicated states. In each case, locate the state by hand on sketches of the p-v and T-v diagrams.
(a) At \(p=20 \mathrm{lbf} / \mathrm{in}^2, v=16 \mathrm{ft}^3 / \mathrm{lb}\), find T in \({ }^{\circ} \mathrm{F}\) and u in \(\mathrm{Btu} / \mathrm{lb}\).
(b) At \(T=900^{\circ} \mathrm{F}, p=170 \mathrm{lbf} / \mathrm{in}^2\), find v in \(\mathrm{ft}^3 / \mathrm{lb}\) and h in \(\mathrm{Btu} / \mathrm{lb}\).
(c) At \(T=600^{\circ} \mathrm{F}, v=0.6 \mathrm{ft}^3 / \mathrm{lb}\), find p in \(\mathrm{lbf} / \mathrm{in}^2\) and u in \(\mathrm{Btu} / \mathrm{lb}\).
(d) At \(T=40^{\circ} \mathrm{F}, v=1950 \mathrm{ft}^3 / \mathrm{lb}\), find p in \(\mathrm{lbf} / \mathrm{in} .^2\) and h in \(\mathrm{Btu} / \mathrm{lb}\).
(e) At \(p=600 \mathrm{lbf} / \mathrm{in.}^2, T=320^{\circ} \mathrm{F}\), find v in \(\mathrm{ft}^3 / 1 \mathrm{~b}\) and u in Btu/lb.
Questions & Answers
QUESTION:
Using the tables for water, determine the specified property data at the indicated states. In each case, locate the state by hand on sketches of the p-v and T-v diagrams.
(a) At \(p=20 \mathrm{lbf} / \mathrm{in}^2, v=16 \mathrm{ft}^3 / \mathrm{lb}\), find T in \({ }^{\circ} \mathrm{F}\) and u in \(\mathrm{Btu} / \mathrm{lb}\).
(b) At \(T=900^{\circ} \mathrm{F}, p=170 \mathrm{lbf} / \mathrm{in}^2\), find v in \(\mathrm{ft}^3 / \mathrm{lb}\) and h in \(\mathrm{Btu} / \mathrm{lb}\).
(c) At \(T=600^{\circ} \mathrm{F}, v=0.6 \mathrm{ft}^3 / \mathrm{lb}\), find p in \(\mathrm{lbf} / \mathrm{in}^2\) and u in \(\mathrm{Btu} / \mathrm{lb}\).
(d) At \(T=40^{\circ} \mathrm{F}, v=1950 \mathrm{ft}^3 / \mathrm{lb}\), find p in \(\mathrm{lbf} / \mathrm{in} .^2\) and h in \(\mathrm{Btu} / \mathrm{lb}\).
(e) At \(p=600 \mathrm{lbf} / \mathrm{in.}^2, T=320^{\circ} \mathrm{F}\), find v in \(\mathrm{ft}^3 / 1 \mathrm{~b}\) and u in Btu/lb.
ANSWER:Step 1 of 6
(a)
Given data:
Pressure
Specific volume
From the saturated water tables,
At
Because is between these values, this means that water is a liquid-vapor mixture.
Therefore, the value of temperature is .