Solution Found!
Suppose the sample in Exercise 7.64 has produced = .83 and
Chapter 7, Problem 65E(choose chapter or problem)
Suppose the sample in Exercise 7.64 has produced \(\hat{p}=.83\) and we wish to test \(H_0: p=.9\) against the alternative \(H_{\mathrm{a}}: p<.9\)
a. Calculate the value of the z-statistic for this test.
b. Note that the numerator of the z-statistic \(\left(\hat{p}-p_0=\right.\) \(.83-.90=-.07)\) is the same as for Exercise 7.64. Considering this, why is the absolute value of z for this exercise larger than that calculated in Exercise 7.64?
c. Complete the test using \(\alpha=.05\) and interpret the result.
d. Find the observed significance level for the test and interpret its value.
Questions & Answers
QUESTION:
Suppose the sample in Exercise 7.64 has produced \(\hat{p}=.83\) and we wish to test \(H_0: p=.9\) against the alternative \(H_{\mathrm{a}}: p<.9\)
a. Calculate the value of the z-statistic for this test.
b. Note that the numerator of the z-statistic \(\left(\hat{p}-p_0=\right.\) \(.83-.90=-.07)\) is the same as for Exercise 7.64. Considering this, why is the absolute value of z for this exercise larger than that calculated in Exercise 7.64?
c. Complete the test using \(\alpha=.05\) and interpret the result.
d. Find the observed significance level for the test and interpret its value.
ANSWER:Step 1 of 5
It is given that =0.83 and
Using this we need to find the required values.