Solution Found!
Let be a particular value of . Find the value of such that
Chapter 7, Problem 82E(choose chapter or problem)
Let \(X_{0}^{2}\) be a particular value of \(X^2\). Find the value of \(X_{0}^{2}\) such that
a. \(P\left(x^{2}\ >\ x_{0}^{2}\right)=.10 \text { for } n=12\)
b. \(P\left(x^{2}\ >\ x_{0}^{2}\right)=.05 \text { for } n=9\)
c. \(P\left(x^{2}\ >\ x_{0}^{2}\right)=.025 \text { for } n=5\)
Questions & Answers
QUESTION:
Let \(X_{0}^{2}\) be a particular value of \(X^2\). Find the value of \(X_{0}^{2}\) such that
a. \(P\left(x^{2}\ >\ x_{0}^{2}\right)=.10 \text { for } n=12\)
b. \(P\left(x^{2}\ >\ x_{0}^{2}\right)=.05 \text { for } n=9\)
c. \(P\left(x^{2}\ >\ x_{0}^{2}\right)=.025 \text { for } n=5\)
ANSWER:Solution:
Step 1 of 3:
Let be the particular value of
- We have P(> ) = 0.10 for n = 12
The claim is to find the value of
We have n = 12 and df = n - 1
= 12 - 1
= 11
We have to check for 11th row and 0.10 column in chi-square table
Therefore, = 17.275.