For each reaction listed, identify the proton donor or acid and the proton acceptor or base. Label each conjugate acid-base pair. a. CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) b. HC O 3- (aq) + H2O(l) H2CO3(aq) + OH-(aq) c. HNO3 + S O 42 - - HS O 4- + N O 3- 2
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General review from 222: (If you need a more thorough review, I have oodles of Chem 222 materials available) Molarity is in units of moles solute per liter solution, or millimoles of solute per milliliters of solution. Molarity times volume equals moles. You will be making your own solutions in lab now, the TA will not make it for you, so it is important that you know how to prepare a dilute solution from a concentrated stock solution. % by mass: mass solute/mass total * 100%. This is unitless. Parts per million: mass solute/mass total * 1,000,000. Units are mg/kg or mg/L for dilute aqueous solution. (One liter of water weighs one kilogram, so liter and kilogram can be used interchangeably.) To prepare a 20 ppm solution NaCl, you would weigh out 20 mg NaCl and add it to 1 liter of wa
Textbook: Modern Chemistry: Student Edition 2012
Author: Jerry L. Sarquis, Mickey Sarquis
This full solution covers the following key subjects: . This expansive textbook survival guide covers 98 chapters, and 1789 solutions. Modern Chemistry: Student Edition 2012 was written by and is associated to the ISBN: 9780547586632. The answer to “For each reaction listed, identify the proton donor or acid and the proton acceptor or base. Label each conjugate acid-base pair. a. CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) b. HC O 3- (aq) + H2O(l) H2CO3(aq) + OH-(aq) c. HNO3 + S O 42 - - HS O 4- + N O 3- 2” is broken down into a number of easy to follow steps, and 54 words. This textbook survival guide was created for the textbook: Modern Chemistry: Student Edition 2012, edition: 1. The full step-by-step solution to problem: 14.1.34 from chapter: 14 was answered by , our top Chemistry solution expert on 01/04/18, 09:13PM. Since the solution to 14.1.34 from 14 chapter was answered, more than 264 students have viewed the full step-by-step answer.