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To keep her dog from running away while she talks to a
Chapter 7, Problem 16P(choose chapter or problem)
To keep her dog from running away while she talks to a friend, Susan pulls gently on the dog's leash with a constant force given by \(\mathrm{\vec{F}=(2.2\ N)\hat{x}+(1.1\ N)\hat{y}}\). How much work does she do on the dog if its displacement is (a) \(\mathrm {\vec{d}=(0.25\ m)\hat{x}}\), (b) \(\mathrm {\vec{d}=(0.25\ m)\hat{y}}\), or (c) \(\mathrm {\vec{d}=(-0.50 m)\hat{x}+(-0.25 m)\hat{y}}\)?
Questions & Answers
QUESTION:
To keep her dog from running away while she talks to a friend, Susan pulls gently on the dog's leash with a constant force given by \(\mathrm{\vec{F}=(2.2\ N)\hat{x}+(1.1\ N)\hat{y}}\). How much work does she do on the dog if its displacement is (a) \(\mathrm {\vec{d}=(0.25\ m)\hat{x}}\), (b) \(\mathrm {\vec{d}=(0.25\ m)\hat{y}}\), or (c) \(\mathrm {\vec{d}=(-0.50 m)\hat{x}+(-0.25 m)\hat{y}}\)?
ANSWER:Step 1 of 4
a.)
We have to find the work done by Susan in pulling the dog’s leash gently with a constant force to keep her dog from running away.
The work done by Susan is given by,
\(W=F_{x} \cdot d_{x}\)
Where,
\(F_{x}=\text {constant force}=[(2.2) \ \hat x+(1.1) \ \hat y]\)
\(d_{x}=\text {displacement}=(0.25) \ \hat x\)