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To balance a 35.5-kg automobile tire and wheel, a mechanic
Chapter 9, Problem 75GP(choose chapter or problem)
Problem 75GP
To balance a 35.5-kg automobile tire and wheel, a mechanic must place a 50.2-g lead weight 25.0 cm from the center of the wheel. When the wheel is balanced, its center of mass is exactly fat the center of the wheel. How far from the center of the wheel was its center of mass before the lead weight was added?
Questions & Answers
QUESTION:
Problem 75GP
To balance a 35.5-kg automobile tire and wheel, a mechanic must place a 50.2-g lead weight 25.0 cm from the center of the wheel. When the wheel is balanced, its center of mass is exactly fat the center of the wheel. How far from the center of the wheel was its center of mass before the lead weight was added?
ANSWER:
Solution 75GP
Step 1 of 2:
An automobile tire and wheel is balanced by placing a lead at the center of mass. The masses of the wheel and the lead are given. We are going to find the location (x2) of the center of mass from the center of the wheel before the addition of the weight.
The mass of the m1 = 50.2 g = 0.0502 kg
The mass of the wheel m2 = 35.5 kg
The distance from the center of wheel to the lead x1 = 25 cm = 0.25 m