An atom in a molecule oscillates about its equilibrium | StudySoup

Textbook Solutions for Physics with MasteringPhysics

Chapter 13 Problem 15P

Question

Molecular Oscillations An atom in a molecule oscillates about its equilibrium position with a frequency of \(2.00 \times 10^{14} \mathrm{~Hz}\) and a maximum displacement of \(3.50 \mathrm{~nm}\). (a) Write an expression giving \(x\) as a function of time for this atom, assuming that \(x=A\) at \(t=0\). (b) If, instead, we assume that \(x=0\) at \(t=0\), would your expression for position versus time use a sine function or a cosine function? Explain.

Solution

a.)

Step 1 of 2

We have to write an expression for displacement as a function of time for an atom oscillating about its equilibrium position with a frequency of  Hz.

The expression for displacement as a function of time is given by,

where,

Amplitude = 3.50 nm

angular speed in rad/s

Now,

Where,

frequency of oscillations

   = Hz

Thus,

     = rad/s

Hence,

Therefore, the expression for displacement as a function of time is .

b.)

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full solution

Title Physics with MasteringPhysics 4 
Author James S. Walker
ISBN 9780321541635

An atom in a molecule oscillates about its equilibrium

Chapter 13 textbook questions

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