When a particle of charge q and momentum p enters a
Chapter 29, Problem 86GP(choose chapter or problem)
When a particle of charge q and momentum enters a uniform magnetic field at right angles it follows a circular path of radius \(R=p / q B\), as shown in Figure 29-32. What radius does this expression predict for a proton traveling with a speed \(v=0.99 c\) through a magnetic field \(B=0.20 T\) if you use
(a) the nonrelativistic momentum \((p=m v)\) or
(b) the relativistic momentum \(\left(p=m v / \sqrt{1-v^{2} / c^{2}}\right)\)?
Equation Transcription:
Text Transcription:
R=p/qB
v=0.99 c
B=0.20 T
(p=mv)
( p=mv/ \sqrt 1 - v2/c2 )
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