Solution Found!
Consider the hospital emergency room data in Example 2-8.
Chapter 2, Problem 76E(choose chapter or problem)
Consider the hospital emergency room data in Example 2-8. Let denote the event that a visit is to hospital 4 , and let
denote the event that a visit results in LWBS (at any hospital). Determine the following probabilities.
(a) \(P(A \cap B)\) (b) \(P\left(A^{\prime}\right)\) (c) \(P(A \cup B)\) (d) \(P\left(A \cup B^{\prime}\right)\) (e) \(P\left(A^{\prime} \cap B^{\prime}\right)\)
equation transcription:
Text transcription:
P(A cap B)
P(A^{prime})
P(A cup B)
P(A cup B^{prime}right)
P(A^{prime} cap B^{prime})
Questions & Answers
QUESTION:
Consider the hospital emergency room data in Example 2-8. Let denote the event that a visit is to hospital 4 , and let
denote the event that a visit results in LWBS (at any hospital). Determine the following probabilities.
(a) \(P(A \cap B)\) (b) \(P\left(A^{\prime}\right)\) (c) \(P(A \cup B)\) (d) \(P\left(A \cup B^{\prime}\right)\) (e) \(P\left(A^{\prime} \cap B^{\prime}\right)\)
equation transcription:
Text transcription:
P(A cap B)
P(A^{prime})
P(A cup B)
P(A cup B^{prime}right)
P(A^{prime} cap B^{prime})
ANSWER:Solution :
Step 1 of 5:
Let A and B be the two events.
A is a visit is to 4 hospital,
B is a visit LWBS or at any hospital.
Then the table is given below.
1 |
2 |
3 |
4 |
Total |
|
Total |
5292 |
6991 |
5640 |
4329 |
22252 |
LWBS |
195 |
270 |
246 |
242 |
953 |
Admitted |
1277 |
1558 |
666 |
984 |
4485 |
Not admitted |
3820 |
5163 |
4728 |
3103 |
16814 |
Our goal is:
Now we have to determine the following probabilities.
a). We need to find .
b). We need to find .
c). We need to find .
d). We need to find .
e). We need to find .
a). Now we have to find P(AB).
P(AB) =
P(AB) = 0.0109
Therefore, P(AB) = 0.0109.