Solution Found!
Consider the endothermic reaction’s in Exercise 2-50. Let
Chapter 2, Problem 74E(choose chapter or problem)
Consider the endothermic reaction’s in Exercise 2-50. Let denote the event that a reaction's inal temperature is 271 K or less. Let
denote the event that the heat absorbed is above target.
Determine the following probabilities.
(a)\(P(A \cap B)\) (b) \(P\left(A^{\prime}\right)\) (c) \(P(A \cup B)\) (d) \(P\left(A \cup B^{\prime}\right)\) (e) \(P\left(A^{\prime} \cap B^{\prime}\right)\)
Equation transcription:
Text transcription:
P(A cap B)
P(A^{prime})
P(A cup B)
P(A cup B^{prime})
P(A^{prime} cap B^{prime})
Questions & Answers
QUESTION:
Consider the endothermic reaction’s in Exercise 2-50. Let denote the event that a reaction's inal temperature is 271 K or less. Let
denote the event that the heat absorbed is above target.
Determine the following probabilities.
(a)\(P(A \cap B)\) (b) \(P\left(A^{\prime}\right)\) (c) \(P(A \cup B)\) (d) \(P\left(A \cup B^{\prime}\right)\) (e) \(P\left(A^{\prime} \cap B^{\prime}\right)\)
Equation transcription:
Text transcription:
P(A cap B)
P(A^{prime})
P(A cup B)
P(A cup B^{prime})
P(A^{prime} cap B^{prime})
ANSWER:Solution :
Step 1 of 5:
Let A and B be the two events.
A = a reaction’s final temperature is 271k or less.
B = the heat absorbed is above target.
Then the table is given below.
Final Temperature Conditions |
Heat Absorbed (cal) |
|
Below Target |
Above Target |
|
266 K |
12 |
40 |
271 K |
44 |
16 |
274 K |
56 |
36 |
Our goal is:
a). We need to find .
b). We need to find .
c). We need to find .
d). We need to find .
e). We need to find .
a). Now we have to find .
Then is
0.2745
Therefore, 0.2745.