Solution Found!
A confidence interval estimate is desired for the gain in
Chapter 8, Problem 4E(choose chapter or problem)
A confidence interval estimate is desired for the gain in a circuit on a semiconductor device. Assume that gain is normally distributed with standard deviation \(\mathrm{s}=20\).
(a) Find a 95% CI for m when \(n=10\) and \(\bar{x}=1000\).
(b) Find a 95% CI for m when \(n=25\) and \(\bar{x}=1000\).
(c) Find a 99% CI for m when \(n=10\) and \(\bar{x}=1000\).
(d) Find a 99% CI for m when \(n=25\) and \(\bar{x}=1000\).
(e) How does the length of the CIs computed change with the changes in sample size and conidence level?
Equation Transcription:
Text Transcription:
s=20
n=10
x bar=1000
n=25
x bar=1000
n=10
x bar=1000
n=25
x bar=1000
Questions & Answers
QUESTION:
A confidence interval estimate is desired for the gain in a circuit on a semiconductor device. Assume that gain is normally distributed with standard deviation \(\mathrm{s}=20\).
(a) Find a 95% CI for m when \(n=10\) and \(\bar{x}=1000\).
(b) Find a 95% CI for m when \(n=25\) and \(\bar{x}=1000\).
(c) Find a 99% CI for m when \(n=10\) and \(\bar{x}=1000\).
(d) Find a 99% CI for m when \(n=25\) and \(\bar{x}=1000\).
(e) How does the length of the CIs computed change with the changes in sample size and conidence level?
Equation Transcription:
Text Transcription:
s=20
n=10
x bar=1000
n=25
x bar=1000
n=10
x bar=1000
n=25
x bar=1000
ANSWER:
Step 1 of 5
Given that,
A confidence interval estimate is desired for the gain in a circuit on a semiconductor device. Assume that gain is normally distributed with standard deviation s = 20.
(a)
It is required to find a 95% CI for m when n = 10 and = 1000.
The 95% confidence level means a 0.05 significance level. The z-critical value is:
The 95% confidence interval for m is obtained by the formula:
Therefore, the required confidence interval is .