The evaporator of a refrigeration cycle is basically a

Chapter 5, Problem 85P

(choose chapter or problem)

The evaporator of a refrigeration cycle is basically a heat exchanger in which a refrigerant is evaporated by absorbing heat from a fluid. Refrigerant-22 enters an evaporator at \(200 \mathrm{kPa}\) with a quality of 22 percent and a flow rate of \(2.65 \mathrm{~L} / \mathrm{h} . \mathrm{R}-22\) leaves the evaporator at the same pressure superheated by \(5^{\circ} \mathrm{C}\). The refrigerant is evaporated by absorbing heat from air whose flow rate is \(0.75 \mathrm{~kg} / \mathrm{s}\). Determine (a) the rate of heat absorbed from the air and (b) the temperature change of air. The properties of R-22 at the inlet and exit of the condenser are \(h_{1}=220.2 \mathrm{~kJ} / \mathrm{kg}, v_{1}=0.0253 \mathrm{~m}^{3} / \mathrm{kg}\), and \(h_{2}=398.0 \mathrm{~kJ} / \mathrm{kg}\).

Equation Transcription:

Text Transcription:

200 kPa

2.65 L/h

5 degree celsius

0.75 kg/s

h_1=220.2 kJ/kg,v_1=0.0253 m^3/kg

h_2=398.0 kJ/kg