A long roll of 2-m-wide and 0.5-cm-thick 1-Mn manganese
Chapter 5, Problem 100P(choose chapter or problem)
A long roll of 2-m-wide and 0.5-cm-thick 1-Mn manganese steel plate \(\left(\rho=7854 \mathrm{~kg} / \mathrm{m}^{3}\right.\) and \(c_{p}=\) \(0.434 \mathrm{~kJ} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\) ) coming off a furnace at \(820^{\circ} \mathrm{C}\) is to be quenched in an oil bath at \(45^{\circ} \mathrm{C}\) to a temperature of \(51.1^{\circ} \mathrm{C}\). If the metal sheet is moving at a steady velocity of \(10 \mathrm{~m} / \mathrm{min}\), determine the required rate of heat removal from the oil to keep its temperature constant at \(45^{\circ} \mathrm{C}\).
Equation Transcription:
2-m
45°C
51.1°C
Text Transcription:
2-m
0.5-cm
rho=7854 kg/m^3
c_p= 0.434 kJ/kg dot degree celsius
820 degree celsius
45 degree celsius
51.1 degree celsius
10 m/min
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