Liquid propane (C3H8) enters a steady-flow combustion
Chapter 15, Problem 85P(choose chapter or problem)
Liquid propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) enters a steady-flow combustion chamber at \(25^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) at a rate of \(0.4 \mathrm{~kg} / \mathrm{min}\) where it is mixed and burned with 150 percent excess air that enters the combustion chamber at \(12^{\circ} \mathrm{C}\). If the combustion products leave at \(1200 \mathrm{~K}\) and \(1 \mathrm{~atm}\), determine (a) the mass flow rate of air, (b) the rate of heat transfer from the combustion chamber, and (c) the rate of entropy generation during this process. Assume \(T_{0}=25^{\circ} \mathrm{C}\).
Equation Transcription:
Text Transcription:
(C_3H_8)
25^circC
1 atm
0.4 kg/min
12^circC
1200 K
1 atm
T_0=25^circC
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer