Solved: Solve {showing details):
Chapter 4, Problem 4.1.88(choose chapter or problem)
Solve (showing details):
\(y_{1}^{\prime} =4 y_{2}+5 e^{t}\)
\(y_{2}^{\prime} =-y_{1}-20 e^{-t}\)
\(y_{1}(0) =1, y_{2}(0)=0\)
Text Transcription:
y_1’ = 4y_2 + 5e^t
y_2’ = -y_1 - 20e^-t
y_1(0) = 1, y_2(0) = 0
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