Answer: Solve {showing details):
Chapter 4, Problem 4.1.91(choose chapter or problem)
Solve (showing details):
\(y_{1}^{\prime} =4 y_{2}+3 e^{3 t}\)
\(y_{2}^{\prime} =2 y_{2}-15 e^{-3 t}\)
\(y_{1}(0) =2, y_{2}(0)=2\)
Text Transcription:
y_1’ = 4y_2 + 3e^3t
y_2’ = 2y_2 - 15e^-3t
y_1(0) = 2, y_2(0) = 2
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer