Solved: Polar coordinates p = Yr + y2, e = arctan (ylx) 13
Chapter 9, Problem 9.1.175(choose chapter or problem)
Polar coordinates \(\rho=\sqrt{x^{2}+y^{2}}, \theta=\arctan (y / x)\) give \(\ell=\int_{\alpha}^{\beta} \sqrt{\rho^{2}+\rho^{\prime 2}} d \theta, \text { where } \rho^{\prime}=d \rho / d \theta\). Derive \(\rho=a(1-\cos \theta)\). Sketch this curve. Hint. Use (10) in App. 3.1.
Text Transcription:
rho=sqrt x^2+y^2. theta=arctan (y/x)
ell=Int_alpha^beta sqrt rho^2+rho’^2 d theta, theta rho’=dp/d theta
rho=a(1-cos theta)
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer