Solved: (Steiner's theorem6) If IA is the moment of
Chapter 10, Problem 10.1.132(choose chapter or problem)
f \(I_{A}\) is the moment of inertia of a mass distribution of total mass M with respect to an axis A through the center of gravity, show that its moment of inertia \(I_{B}\) with respect to an axis B, which is parallel to A and has the distance k from it. is
\(I_{B}=I_{A}+k^{2} M\).
Text Transcription:
I_A
I_B
I_B = I_A + k^2 M
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