Solved: BAR UNDER ADIABATIC CONDITIONS "Adiabatic" means
Chapter 12, Problem 12.1.86(choose chapter or problem)
(Discontinuous f) Solve (1), (2), (3) with \(L=\pi\) and \(f(x)=U_{0}=\text { const }(\neq 0) \text { if } 0<x<\pi / 2\), \(f(x)=0 \text { if } \pi / 2<x<\pi\).
Text Transcription:
L=pi
f(x)=U_0=const (neq 0) if 0 < x < pi/2
f(x)=0 if pi/2 < x < pi
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