# How far out on the diving board (Fig. 9–42) would a 58-kg

## Problem 4P Chapter 9

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition

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Problem 4P

How far out on the diving board (Fig. 9–42) would a 58-kg diver have to be to exert a torque of 1100m · N on the board, relative to the left (A) support post?

FIGURE 9–42

Step-by-Step Solution:

Solution 4P Step 1 of 3 The area unde r the -t graph will gives the impulse produced. From the figure, the graph represents a triangle. So, the area under the graph is, J= Area under the graph J= (base)(height) 2 Here, J is the impulse. Step 2 of 3 In the graph time axis represents the base and force axis represents the height. Therefore, base is given by, Base=(8ms-0ms) Height is given by, Height=(F max-0)

Step 3 of 3

##### ISBN: 9780130606204

This full solution covers the following key subjects: figure, gives, Impulse. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6th. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. Since the solution to 4P from 9 chapter was answered, more than 359 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 4P from chapter: 9 was answered by , our top Physics solution expert on 03/03/17, 03:53PM. The answer to “How far out on the diving board (Fig. 9–42) would a 58-kg diver have to be to exert a torque of 1100m · N on the board, relative to the left (A) support post?FIGURE 9–42” is broken down into a number of easy to follow steps, and 35 words.

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