This problem shows in two ways that detA = 0 (the xs are any numbers): A = x x x x x x x

Chapter 4, Problem 4.3.16

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This problem shows in two ways that detA = 0 (the xs are any numbers): A = x x x x x x x x x x 0 0 0 x x 0 0 0 x x 0 0 0 x x . 5 by 5 matrix 3 by 3 zero matrix Always singular (a) How do you know that the rows are linearly dependent? (b) Explain why all 120 terms are zero in the big formula for detA.

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