What is the minimum-length least-squares solution x + = A +b to the following? Ax = 1 0
Chapter 6, Problem 6.3.18(choose chapter or problem)
What is the minimum-length least-squares solution x + = A +b to the following? Ax = 1 0 0 1 0 0 1 1 1 C D E = 0 2 2 . You can compute A +, or find the general solution to A TAxb= A Tb and choose the solution that is in the row space of A. This problem fits the best plane C+Dt +Ez to b = 0 and also b = 2 at t = z = 0 (and b = 2 at t = z = 1). (a) If A has independent columns, its left-inverse (A TA) 1A T is A +. (b) If A has independent rows, its right-inverse A T (AAT ) 1 is A +. In both cases, verify that x + = A +b is in the row space. and A TAx+ = A Tb.
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