A branch voltage in an RLC circuit is described by d2v _ dt2 + 4 dv _ dt + 8v = 24

Chapter 8, Problem 8.27

(choose chapter or problem)

A branch voltage in an $RLC$ circuit is described by

$\frac{d^{2} v}{d t^{2}}+4 \frac{d v}{d t}+8 v=24$

If the initial conditions are $v(0) = 0 = dv(0)/dt$, find $v(t)$.

Equation Transcription:

$RLC$

$\frac{{d}^{2}v}{{dt}^{2}}+4\frac{dv}{dt}+8v=24$

$v(0)\ =\ 0\ =\ dv(0)/dt$

$v(t)$

Text Transcription:

RLC

d^2v/dt^2+4dv/dt+8v=24

v(0) = 0 = dv(0)/dt

v(t)

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