Consider the equation 6 (x 3)(x 1) = 3 x 3 + 4 x 1 . Without performing any
Chapter 2, Problem 85(choose chapter or problem)
Consider the equation
\(\frac{6}{(x-3)(x-1)}=\frac{3}{x-3}+\frac{4}{x-1}\)
Without performing any calculations, explain how to clear this equation of fractions. Is it possible that this process will introduce an extraneous solution? If so, describe two ways to determine whether a solution is extraneous.
Text Transcription:
6 / (x − 3)(x − 1) = 3 / x − 3 + 4 / x − 1
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