Solution Found!
The length of each of the two equal sides of an isosceles triangle is 10 meters (see
Chapter 6, Problem 124(choose chapter or problem)
The length of each of the two equal sides of an isosceles triangle is 10 meters (see figure). The angle between the two sides is \(\theta\).
(a) Write the area of the triangle as a function of \(\theta / 2\).
(b) Write the area of the triangle as a function of \(\theta\) and determine the value of \(\theta\) such that the area is a maximum.
Questions & Answers
QUESTION:
The length of each of the two equal sides of an isosceles triangle is 10 meters (see figure). The angle between the two sides is \(\theta\).
(a) Write the area of the triangle as a function of \(\theta / 2\).
(b) Write the area of the triangle as a function of \(\theta\) and determine the value of \(\theta\) such that the area is a maximum.
ANSWER:Step 1 of 5
(a)
We need to find the area function of the triangle in terms of \(\frac{\theta}{2}\).
The area of a triangle with base b and corresponding height h is given by
\(A=\frac{1}{2} b h\)